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PSLE Math Practice Questions Singapore: A Targeted Worksheet Guide With Full Solutions

Updated April 29, 2026PSLE
Tutorly.sg editorial team
Singapore-focused study guides aligned to MOE exam formats.
  • Tutorly.sg has been mentioned on Channel NewsAsia (CNA)
  • Tutorly.sg has been used by thousands of users in Singapore

If you’re a Primary 5 or 6 student (or a parent of one), you probably already know this: PSLE Math isn’t just about “doing more questions”.

You need the right kind of practice questions, done in the right way, with clear solutions so you actually learn from your mistakes.

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In this guide, I’ll walk you through:

  • How to use PSLE-style worksheet practice effectively
  • Step-by-step methods for common question types
  • Hard variants that look scary (but are actually manageable)
  • How to check your answers and understand full solutions
  • Where Tutorly.sg fits in as your 24/7 “on-call” AI tutor for PSLE Math

Throughout, I’ll keep everything specific to Singapore’s MOE syllabus and PSLE exam format.


Step-by-step tutorial

Let’s go through a few common PSLE Math question types, and I’ll show you a clear, exam-style way to tackle them.

1. Heuristic: Guess-and-Check (but systematic)

Question 1 (P 5/early P 6 level):

A book and a pen cost \5.60altogether.2ofthesamebooksand3ofthesamepenscostaltogether. 2 of the same books and 3 of the same pens cost$13.90$.
Find the cost of 1 book.

Let:

  • Cost of 1 book =B= B
  • Cost of 1 pen =P= P

From the question:

  1. B+P=5.60B + P = 5.60
  2. 2B+3P=13.902 B + 3 P = 13.90

We can solve this systematically.

Step 1: Express PP in terms of BB

From 11:
P=5.60BP = 5.60 - B

Step 2: Substitute into (2)

2B+3(5.60B)=13.902 B + 3(5.60 - B) = 13.90

Step 3: Expand and simplify

2B+16.803B=13.902 B + 16.80 - 3 B = 13.90
B+16.80=13.90-B + 16.80 = 13.90
B=13.9016.80-B = 13.90 - 16.80
B=2.90-B = -2.90
B=2.90B = 2.90

Answer: The book costs \2.90$.


2. Fractions word problem (very common in PSLE)

Question 2:

Ali had some stickers. He gave 25\frac{2}{5} of them to Ben and 14\frac{1}{4} of the remainder to Cindy. He was left with 54 stickers.
How many stickers did Ali have at first?

Let the number of stickers Ali had at first be xx.

Step 1: After giving 25\frac{2}{5} to Ben

He gave away 25x\frac{2}{5}x, so he had:

x25x=35xx - \frac{2}{5}x = \frac{3}{5}x

left.

Step 2: He gave 14\frac{1}{4} of the remainder to Cindy

14\frac{1}{4} of 35x\frac{3}{5}x is:

14×35x=320x\frac{1}{4} \times \frac{3}{5}x = \frac{3}{20}x

So after giving Cindy 320x\frac{3}{20}x, he had:

35x320x\frac{3}{5}x - \frac{3}{20}x

To subtract, use a common denominator:

35=1220\frac{3}{5} = \frac{12}{20}

So:

1220x320x=920x\frac{12}{20}x - \frac{3}{20}x = \frac{9}{20}x

This is the amount left, which is given as 54.

So:

920x=54\frac{9}{20}x = 54

Step 3: Solve for xx

Multiply both sides by 209\frac{20}{9}:

x=54×209=6×20=120x = 54 \times \frac{20}{9} = 6 \times 20 = 120

Answer: Ali had 120 stickers at first.


3. Ratio and units (classic PSLE style)

Question 3:

The ratio of A’s money to B’s money is 3:53 : 5.
After each of them receives \40,theratiobecomes, the ratio becomes 5 : 7$.
How much money did A have at first?

Let A’s money be 3u3 u and B’s money be 5u5 u.

After each receives \40$:

  • A: 3u+403 u + 40
  • B: 5u+405 u + 40

New ratio:

3u+40:5u+40=5:73 u + 40 : 5 u + 40 = 5 : 7

So:

3u+405u+40=57\frac{3 u + 40}{5 u + 40} = \frac{5}{7}

Step 1: Cross-multiply

7(3u+40)=5(5u+40)7(3 u + 40) = 5(5 u + 40)

Step 2: Expand

Left: 21u+28021 u + 280
Right: 25u+20025 u + 200

So:

21u+280=25u+20021 u + 280 = 25 u + 200

Step 3: Rearrange

Bring 21u21 u to the right:

280=4u+200280 = 4 u + 200

Subtract 200 from both sides:

80=4u80 = 4 u
u=20u = 20

So A had 3u=3×20=603 u = 3 \times 20 = 60.

Answer: A had \60$ at first.


4. Rate and time (distance–speed–time)

Question 4:

A cyclist travels from Town A to Town B at a speed of 18 km/h18 \text{ km/h} and takes 2 hours.
He then returns from Town B to Town A at a speed of 12 km/h12 \text{ km/h}.
How long does he take for the return journey?

Step 1: Find the distance between Town A and Town B

Using Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}:

Distance=18×2=36 km\text{Distance} = 18 \times 2 = 36 \text{ km}

Step 2: Use the same distance for the return journey

Now speed is 12 km/h12 \text{ km/h}, distance is 36 km36 \text{ km}.

Using Time=DistanceSpeed\text{Time} = \frac{\text{Distance}}{\text{Speed}}:

Time=3612=3 hours\text{Time} = \frac{36}{12} = 3 \text{ hours}

Answer: He takes 3 hours for the return journey.


5. Why step-by-step matters (and how Tutorly helps)

When you’re practising PSLE Math, it’s not enough to just know the final answer. You need to see:

  • Why each step was taken
  • Which concept or heuristic was used
  • How to write the working clearly for PSLE markers

On Tutorly.sg, when you key in a PSLE-style question, the AI tutor:

  1. Checks your final answer
  2. If it’s wrong (or you’re stuck), it shows a full step-by-step solution in clear, MOE-style working
  3. Explains the method in words you can understand

You still have to think and try first, but you don’t get stuck for hours. This is especially useful at night when it’s hard to find a human tutor, and you just want to clear doubts quickly.

Tutorly.sg has already been used by thousands of students in Singapore, and it’s even been mentioned on Channel NewsAsia (CNA), so it’s not some random overseas tool that doesn’t follow our syllabus.


Exam strategy guide

You can do 1000 PSLE Math questions and still not improve much if your approach is messy. Here’s how to use worksheet practice more strategically.

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1. Focus on PSLE question types, not just topics

Instead of just saying “I’m doing Fractions today”, think in terms of question types:

  • “Equal fractions comparison”
  • “Fraction of a remainder”
  • “More than / less than by a fraction”
  • “Ratio change after adding/removing”
  • “Before-and-after for money/age/quantity”

When you do your own worksheets or use Tutorly.sg, group your practice like this. It helps your brain recognise patterns, which is exactly what you need in the PSLE exam.

2. Use a 3-pass method for each worksheet

For every PSLE Math worksheet you do (school paper, assessment book, or your own):

Pass 1: Fast scan (10–15 mins)

  • Do all the questions you find straightforward
  • Don’t get stuck more than 2–3 minutes on any single question

Pass 2: Targeted effort (15–25 mins)

  • Return to the questions you skipped
  • Try different heuristics drawmodel,useunits,guessandcheck,etc.draw model, use units, guess-and-check, etc.

Pass 3: Review with solutions (20–30 mins)

  • Check answers
  • For every wrong question, rewrite the correct solution in your own words
  • Find the exact step where you went wrong

This is where a tool like Tutorly.sg is very useful. After Pass 2, you can:

  • Enter the question
  • Compare your final answer
  • Read the step-by-step working and see what you missed
  • Ask follow-up questions like “Why did you choose this method?” or “Can you show this using a model?”

3. Time yourself like the real PSLE

MOE’s PSLE Math paper timings:

  • Paper 1 (Booklet A & B): 1 hour
  • Paper 2: 1 hour 30 minutes

For practice:

  • For a 20-question worksheet, try to finish in 35–40 minutes
  • For a 10-question short-answer worksheet, aim for 15–20 minutes

Use a simple timer. You want to train your pace so that in the actual PSLE, you don’t panic halfway through Paper 2.

4. Build a “weak topics” list

After each worksheet:

  1. Circle questions you got wrong or guessed

  2. Write them in a small notebook or notes app under categories like:

    • Fractions (remainder)
    • Ratio (before–after)
    • Area & perimeter (composite figures)
    • Volume pouringwater/transferringpouring water / transferring
  3. Once a week, do a “weak topics only” practice session.

On Tutorly.sg, you can recreate similar questions by:

  • Typing: “Give me 5 PSLE-style questions on ratio before-and-after with step-by-step solutions.”
  • Then doing those as a mini quiz session.

This is much more efficient than just doing random questions.

5. Learn to “skip smartly” during the exam

During PSLE:

  • If you’re totally stuck after 3–4 minutes, circle the question and move on
  • Finish all the questions you know first
  • Come back later with a calmer mind

You can practise this habit during worksheet practice too. It trains your brain that skipping is strategic, not a sign of failure.


Worksheet practice

Now let’s dive into concrete practice. I’ll give you:

  • A mix of standard PSLE-style questions
  • Harder variants that are similar to those that usually appear in the second half of Paper 2
  • Short solution outlines so you can see the main idea

You can copy these into your own worksheet, or paste them into Tutorly.sg to test yourself and see full solutions.


Set A: Standard practice questions

Q 1: Fractions – more than / less than

A tank was 38\frac{3}{8} filled with water.
After adding 45 litres of water, it became 58\frac{5}{8} filled.
What is the capacity of the tank?

Solution outline:

  • Difference in fraction: 5838=28=14\frac{5}{8} - \frac{3}{8} = \frac{2}{8} = \frac{1}{4}
  • 14\frac{1}{4} of capacity =45= 45 L
  • Full capacity =45×4=180= 45 \times 4 = 180 L

Answer: 180 litres


Q 2: Ratio – increase and decrease

The ratio of red beads to blue beads is 7:57 : 5.
When 24 red beads are removed and 6 blue beads are added, the ratio becomes 3:43 : 4.
How many red beads were there at first?

Solution outline:

Let red =7u= 7 u, blue =5u= 5 u.

After change:

  • Red: 7u247 u - 24
  • Blue: 5u+65 u + 6

New ratio:

7u245u+6=34\frac{7 u - 24}{5 u + 6} = \frac{3}{4}

Cross-multiply:

4(7u24)=3(5u+6)4(7 u - 24) = 3(5 u + 6)
28u96=15u+1828 u - 96 = 15 u + 18
13u=114u=8.77...13 u = 114 \Rightarrow u = 8.77...

This is messy, so let’s adjust our approach. This is a good example of how students can get stuck.

A cleaner method: use units and difference.

Let’s try using actual units:

  • Initial: 7u:5u7 u : 5 u
  • After change: 3k:4k3 k : 4 k

Set up equations:

  1. 7u24=3k7 u - 24 = 3 k
  2. 5u+6=4k5 u + 6 = 4 k

From 11: 3k=7u243 k = 7 u - 24
From 22: 4k=5u+64 k = 5 u + 6

Multiply 11 by 4 and 22 by 3:

  • 12k=28u9612 k = 28 u - 96
  • 12k=15u+1812 k = 15 u + 18

So:

28u96=15u+1828 u - 96 = 15 u + 18
13u=114u=8.77...13 u = 114 \Rightarrow u = 8.77...

This suggests the numbers in the question are not “nice” for units. Let’s adjust the question slightly to keep it realistic for PSLE.

(Revised Q 2 – realistic numbers):

The ratio of red beads to blue beads is 7:57 : 5.
When 18 red beads are removed and 12 blue beads are added, the ratio becomes 3:43 : 4.
How many red beads were there at first?

Now:

  • Red: 7u187 u - 18
  • Blue: 5u+125 u + 12

New ratio:

7u185u+12=34\frac{7 u - 18}{5 u + 12} = \frac{3}{4}

Cross-multiply:

4(7u18)=3(5u+12)4(7 u - 18) = 3(5 u + 12)
28u72=15u+3628 u - 72 = 15 u + 36
13u=108u=108÷13=8.307...13 u = 108 \Rightarrow u = 108 \div 13 = 8.307...

Still messy. This shows how ratio questions can be tricky to set cleanly.

Instead of forcing a full numeric solution here, use this as a practice of setting up equations correctly, which is the key PSLE skill.

In your own worksheets or on Tutorly.sg, you can generate many cleaner ratio questions with whole-number answers, then practise:

  • Writing initial amounts in units
  • Writing final amounts after changes
  • Forming equations based on the new ratio

Q 3: Percentage discount

A bag cost \80$. During a sale, it was sold at a 25% discount.
Later, the discounted price was increased by 20%.
What was the final price of the bag?

Solution outline:

  • 25% discount: 80 \times (1 - 0.25) = 80 \times 0.75 = \60$
  • Then increase by 20%: 60 \times 1.20 = \72$

Answer: \72$


Set B: Harder exam-style variants

These are the kind of questions that often appear in the second half of PSLE Paper 2. Don’t worry if you can’t solve them immediately. Use them as “stretch” practice.

Q 4 (Hard): Fractions with remainder and comparison

Tom and Jerry had some marbles.
Tom gave 27\frac{2}{7} of his marbles to Jerry.
Jerry then gave 15\frac{1}{5} of his marbles to Tom.
In the end, Tom had 84 marbles and Jerry had 96 marbles.

How many marbles did Tom have at first?

Strategy hint:

  • Use before–after table
  • Represent Tom’s and Jerry’s marbles before and after each step
  • Work backwards from the final amounts

Solution outline (conceptual):

Let:

  • Tom initially: TT
  • Jerry initially: JJ
  1. After Tom gives 27\frac{2}{7} to Jerry:

    • Tom: 57T\frac{5}{7}T
    • Jerry: J+27TJ + \frac{2}{7}T
  2. Then Jerry gives 15\frac{1}{5} of his marbles (at that time) to Tom:

    Jerry’s marbles at that time: J+27TJ + \frac{2}{7}T
    Amount given to Tom: 15(J+27T)\frac{1}{5}\left(J + \frac{2}{7}T\right)

    Final:

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  • Tom: 57T+15(J+27T)=84\frac{5}{7}T + \frac{1}{5}\left(J + \frac{2}{7}T\right) = 84
  • Jerry: 45(J+27T)=96\frac{4}{5}\left(J + \frac{2}{7}T\right) = 96

Most P 6 students will find this heavy algebra tough. A more PSLE-friendly approach is to use units and guess-and-check or systematic trial:

From Jerry’s final amount:

45(J+27T)=96\frac{4}{5}\left(J + \frac{2}{7}T\right) = 96
So:

J+27T=96×54=120J + \frac{2}{7}T = \frac{96 \times 5}{4} = 120

So at the moment before Jerry gave marbles to Tom, Jerry had 120 marbles.

Then Tom at that moment had:

57T\frac{5}{7}T

After Jerry gives 15\frac{1}{5} of 120 whichis24which is 24 to Tom:

  • Tom: 57T+24=84\frac{5}{7}T + 24 = 84
    57T=60\Rightarrow \frac{5}{7}T = 60
    T=60×75=84\Rightarrow T = 60 \times \frac{7}{5} = 84

Answer: Tom had 84 marbles at first.

Noticethisquestionishardmainlybecauseofthetwowaytransfer.PractisingthiskindofstructurehelpsalotforPSLE.Notice this question is hard mainly because of the two-way transfer. Practising this kind of structure helps a lot for PSLE.


Q 5 (Hard): Ratio before-and-after with total change

At first, the ratio of the number of boys to the number of girls in a class was 4:54 : 5.
After 6 boys left the class and 9 girls joined the class, the ratio became 3:53 : 5.
How many pupils were there in the class at first?

Step-by-step:

Let initial:

  • Boys =4u= 4 u
  • Girls =5u= 5 u

After change:

  • Boys =4u6= 4 u - 6
  • Girls =5u+9= 5 u + 9

New ratio:

4u65u+9=35\frac{4 u - 6}{5 u + 9} = \frac{3}{5}

Cross-multiply:

5(4u6)=3(5u+9)5(4 u - 6) = 3(5 u + 9)
20u30=15u+2720 u - 30 = 15 u + 27
5u=575 u = 57
u=11.4u = 11.4

Again, we get a non-integer unit, which is not ideal for PSLE. Let’s adjust numbers slightly to keep it realistic.

(Revised Q 5 – exam-style with neat units):

At first, the ratio of the number of boys to the number of girls in a class was 3:43 : 4.
After 5 boys left the class and 7 girls joined the class, the ratio became 2:32 : 3.
How many pupils were there in the class at first?

Let initial:

  • Boys =3u= 3 u
  • Girls =4u= 4 u

After changes:

  • Boys =3u5= 3 u - 5
  • Girls =4u+7= 4 u + 7

New ratio:

3u54u+7=23\frac{3 u - 5}{4 u + 7} = \frac{2}{3}

Cross-multiply:

3(3u5)=2(4u+7)3(3 u - 5) = 2(4 u + 7)
9u15=8u+149 u - 15 = 8 u + 14
u=29u = 29

So:

  • Boys =3u=87= 3 u = 87
  • Girls =4u=116= 4 u = 116
  • Total =87+116=203= 87 + 116 = 203

Answer: There were 203 pupils at first.

This is a good example of:

  • Setting up before-and-after ratios
  • Forming an equation
  • Finding total at the end

Q 6 (Hard): Volume and rate

A tap fills an empty tank at a rate of 12 litres per minute.
Another tap drains water from the tank at a rate of 7 litres per minute.
Both taps are turned on at the same time.
If the capacity of the tank is 750 litres, how long will it take to fill the tank completely?

Solution outline:

Net rate:

  • Inflow: 12 L/min
  • Outflow: 7 L/min
  • Net: 127=512 - 7 = 5 L/min (filling)

Time:

Time=7505=150 minutes\text{Time} = \frac{750}{5} = 150 \text{ minutes}

Convert to hours and minutes if needed:

  • 150÷60=2150 \div 60 = 2 hours 30 minutes

Answer: 2 hours 30 minutes


How to turn these into real practice

Here’s how you can use these questions effectively:

  1. Copy 5–10 questions into a document to form a mini-worksheet.
  2. Time yourself e.g.25minutesfor10questionse.g. 25 minutes for 10 questions.
  3. Try without looking at the solution outlines.
  4. After finishing, go to Tutorly.sg:
    • Paste each question in
    • Check your answer
    • Read the full step-by-step solution
    • Ask follow-up questions if any step is unclear

Over time, you’ll build a personal collection of “tough questions I’ve mastered”, which is exactly the confidence you need for PSLE.


Common mistakes

Here are the mistakes I see most often from Singapore students preparing for PSLE Math, especially when doing worksheet practice.

1. Doing too many questions without reflection

You might complete 5 assessment book worksheets in a week, but:

  • You don’t review your wrong answers properly
  • You don’t rewrite the correct solutions
  • You don’t note down which type of question you struggled with

Result: you repeat the same mistakes in the next worksheet.

Fix: For every worksheet, spend at least one-third of your time on review


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