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O Level Chemistry: Stoichiometry Practice Questions to Nail the Exam

Updated June 27, 2026O Levels
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Quick answer

Ever felt that sinking feeling when your stoichiometry answer doesn't match the marking scheme? You're not alone. Here's what we'll do: understand common mistakes, work through practice questions, and learn how to present your answers clearly. This way, you'll know if your working will actually score in a real exam.

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What you need to know

Stoichiometry involves calculating the amounts of reactants and products in chemical reactions. It's like solving a puzzle where you use the ratios from the balanced equation to find unknown quantities.

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Common mistakes students make

One mistake I repeatedly see among my Sec 4 students is memorizing without understanding. You might know the keywords but miss the process. Here are some common slips:

  • Not balancing the equation first. Always start with this step; otherwise, all calculations will be off.
  • Ignoring units. Units are crucial in stoichiometry. Convert them correctly to avoid losing marks.
  • Using incorrect molar ratios. Double-check your balanced equation to ensure you're using the right ratios.

Exam tip

In stoichiometry, precision matters more than length. Be clear and concise in your workings. Write each step clearly to show the examiner your thought process. This way, even if your final answer is off, you might still gain method marks.

Worked examples

Question

Calculate the mass of water produced when 5 g of hydrogen reacts with oxygen.

Solution

Step 1: Write the balanced chemical equation: 2𝐻2+𝑂22𝐻2𝑂2𝐻_2 + 𝑂_2 \rightarrow 2𝐻_2𝑂
Why: Balancing ensures we use the correct molar ratios for calculations.

Step 2: Calculate the moles of hydrogen: moles=massmolar mass=52=2.5 moles\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{5}{2} = 2.5 \text{ moles}
Why: Moles link mass and chemical reactions, allowing us to use the balanced equation.

Step 3: Use the molar ratio from the equation (2:2) to find moles of water: 2.5 moles of 𝐻22.5 moles of 𝐻2𝑂2.5 \text{ moles of } 𝐻_2 \rightarrow 2.5 \text{ moles of } 𝐻_2𝑂
Why: The ratio tells us how reactants convert to products.

Step 4: Calculate the mass of water: mass=moles×molar mass of water=2.5×18=45g\text{mass} = \text{moles} \times \text{molar mass of water} = 2.5 \times 18 = 45 \text{g}
Why: This gives us the actual amount of product formed.

Quick check

  1. If 10 g of calcium carbonate decomposes, how much carbon dioxide is produced?
  2. How many moles of oxygen are needed to completely react with 8 g of hydrogen?

Answers:

  1. 4.4 g of CO2CO_2
  2. 4 moles of 𝑂2𝑂_2

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  • Always balance the equation first.
  • Convert units to moles using molar mass.
  • Use the correct molar ratios from the balanced equation.
  • Write each step clearly to show your thought process.
  • Double-check your calculations and units.

FAQ

What if my final answer is wrong?
If your working shows the correct process, you can still earn method marks.

How do I balance equations quickly?
Practice identifying and matching the number of each type of atom on both sides.

Why do we convert to moles?
Moles allow us to use the balanced equation to relate reactants to products.

What's a common unit mistake?
Forgetting to convert grams to moles or using the wrong molar mass.

How do I know if my answer is correct?
Check if your answer matches the expected units and magnitude based on the balanced equation.

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Practise with step-by-step help — free to start

On Tutorly.sg/app you can practise unlimited Singapore syllabus questions, get instant explanations when you are stuck, and use past-year papers — no sign-up needed to start.

  • ✓ PSLE, O Level, A Level, and more
  • ✓ Step-by-step working when you are stuck
  • ✓ Works on phone and laptop
Start practising on Tutorly.sg/app →

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